Math, asked by kunzin5888, 11 months ago

Solve (2X+1)^2-(3X+2)^2=0=

Answers

Answered by janvitha

0

Answer:

-3/5 and -1

Step-by-step explanation:

(4x²+1+2x)-(9x²+4+12x)=0

5x²+8x+3=0

(x+1)(x+3/5)=0

x=-1&-3/5

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