Solve: (2x+1)+
3
(2x+1)
4 x ²
1
2
Answers
Answered by
1
Answer:
plz write this sum in manner.I dont understand your sum
Answered by
26
Answer:
√(2x-1) -√(2x+1) = 1 …(1)
Square both sides of (1) to get
(2x-1) -2√(2x-1)*√(2x+1) + 2x+1 = 1, or
4x-1 = 2√(2x-1)*√(2x+1) = 2√(4x^2–1) …(2)
Square both sides of (2) to get
(4x-1)^2 = 4(4x^2–1), or
16x^2–8x+1 = 16x^1–4, or
-8x = -5, or
x = (5/8)
Therefore, √(4x^2–1) = √[(4*25/64)–1]
= √[100/64)–1]
= √[(100–64)/64]
= √(36/64)
= 6/8
= 0.75. Answer.
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