CBSE BOARD X, asked by 894407448318, 6 months ago

Solve: (2x+1)+
3
(2x+1)
4 x ²
1
2​

Answers

Answered by devendersoni042
1

Answer:

plz write this sum in manner.I dont understand your sum

Answered by ashauthiras
26

Answer:

√(2x-1) -√(2x+1) = 1 …(1)

Square both sides of (1) to get

(2x-1) -2√(2x-1)*√(2x+1) + 2x+1 = 1, or

4x-1 = 2√(2x-1)*√(2x+1) = 2√(4x^2–1) …(2)

Square both sides of (2) to get

(4x-1)^2 = 4(4x^2–1), or

16x^2–8x+1 = 16x^1–4, or

-8x = -5, or  

x = (5/8)

Therefore, √(4x^2–1) = √[(4*25/64)–1]

= √[100/64)–1]

= √[(100–64)/64]

= √(36/64)

= 6/8

= 0.75. Answer.

Similar questions