Solve 2x -18 = 48-x and check your answer
Answers
Answer:
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Step-by-step explanation:
First, subtract 48 from both sides:
x(x+2)-48 = 0
Now, use the FOIL method to distribute the x to the (x+2)
x^2 + 2x - 48 = 0
Now, factor this trinomial:
(x+8)(x-6) = 0
Double-check that the factoring was correct by using the FOIL method to expand it:
x^2 - 6x + 8x - 48
x^2 + 2x - 48
Okay! So the factoring was correct:
(x+8)(x-6) = 0
In order for this to be a true statement you need to look for values of x such that one set of parentheses equals 0, and thus multiplies by the other set of parentheses with a resulting product of 0.
In other words, you need a value for x that cancels out the other term in the parentheses.
The first set of parentheses:
(x+8)
You need to add something to the +8 to make it equal to zero. In this case, you would add -8, and that is your first of the two values of x.
The second set of parentheses:
(x-6)
Again, you need to add something to the -6 to make it equal to zero. In this case the value of x equals 6.
So your two values of x are -8 and +6.
To double-check that these solutions are correct simply substitute for x in the original equation:
x(x+2) = 48
x = -8
-8(-8+2) = 48
-8(-6) = 48
48 = 48
~~~~~~~
x(x+2) = 48
x = 6
6(6+2) = 48
6(8) = 48
48 = 48
So there are two solutions for x to the original equation, and the two solutions are -8 and +6.
Answer:
2x+x =48+18
3x = 66
x = 66/ 3
x = 22
VERIFICATION
Putting in values :
LHS RHS
2(22) -18 48 - 22
44-18
26 26
LHS = RHS
Step-by-step explanation:
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