Math, asked by daytongbergeron, 6 months ago

Solve 2x^2 + 12x − 14 = 0 by completing the square 2(x + 6)^2 = 26; x = −6 + √ 13, x = −6 − √13 2(x + 6)^2 = 20; x = −6 + √20,x=-6-√20 2(x + 3)^2 = 32; x = 1, x = −7 2(x + 3)^2 = 32; x = 13, x = 19 these are the choices btw ^

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Answered by BrainlyHero80
4

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