Question

Solve 2x^2 + 2x – 3 = 0, giving your answer correct up to one decimal place.

Answer 1

Step-by-step explanation:

Hope it helps

Step-by-step explanation:

\begin{gathered}2x^2-2x+3x-3=0\\\\\\2x(x-1)+3(x-1)=0\\\\\\(2x+3)(x-1)=0\\\\\\x=\frac{-3}{2}~~or~~x=1\end{gathered}

2x

2

−2x+3x−3=0

2x(x−1)+3(x−1)=0

(2x+3)(x−1)=0

x=

2

−3

or x=1