Question

Solve 2x^2 - (4+√2)x + 2√2=0

Answer 1

Soln;

2x^2-(4+√2)x+2√2 =0

Or, 2x^2-4x-√2x+2√2=0

Or, 2x(x-2)-√2(x-2)=0

Or, (2x-√2)(x-2)=0

Now;

Either;

2x-√2=0

Or, 2x=√2

Or, x=√2/2

Or, x= √2/2√2

Hence, x=1/2

Or;

X-2=0

Or, x=2

Hence,x=2

Therefore: the value of x is(1/2, 2)

Answer 2

Answer:

x = (-1/√2,2)

Step-by-step explanation:

2x² - (4+√2)x + 2√2=0

2x² - (4+√2)x = -2√2

2x² - 4x+√2x = -2√2

2(x² - 2x+1/√2x) = -2√2

x² - 2x+1/√2x = -√2

x² - √2/√2x = -√2

x² - √2/√2x + √2 = 0

x² - 2x+1/√2x + √2 = 0

x(x-2)+1/√2(x-2) = 0

(x+1/√2)(x-2) = 0

Hence, x = (-1/√2,2)