Math, asked by Piushg0yal, 1 year ago

solve 2x^2+4x-240 by factorisation method

Answers

Answered by kalyaniprasad8
6

2x²+4x-240=0

2x²+24x-20x-240=0

2x(x+12)-20(x+12)=0

(2x-20)(x+12)=0

2x=20 or x=-12

x=10 or -12

Answered by Anonymous
4

Answer:

given \: polynomial \:  =  \\  \\ 2 {x}^{2}  + 4x - 240 \:  \:  = 0

Taking 2 common

  {x}^{2}  + 2x - 120 \:  = 0

By mid term splitting.

 {x}^{2}  + 12x - 10x - 120 = 0

x(x + 12) - 10(x + 12)

(x - 10)(x + 12) = 0 \\  \\ x = 10 \\  \\ x =  - 12

Hope it may help you

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