solve 2x^2+8x+4=0. find the value of x in above equation
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Hey!!!!
We have
=> 2x² + 8x + 4 = 0
=> 2x² + 4x + 4x + 4 = 0
=> 2x(x + 2) + 4(x + 2) = 0
=> (2x + 4)(x + 2) = 0
Thus x = -2 and again -2
Hope this helps
We have
=> 2x² + 8x + 4 = 0
=> 2x² + 4x + 4x + 4 = 0
=> 2x(x + 2) + 4(x + 2) = 0
=> (2x + 4)(x + 2) = 0
Thus x = -2 and again -2
Hope this helps
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