solve 2x-3/2x+1=3x+1/3x-1
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(2x-3)/(2x+1) = (3x+1)/ 3x-1
After cross multiplying, we'll get
(2x-3)×(3x-1)= (3x+1)(2x+1)
=> 6x^2 - 2x - 9x+ 3 = 6x^2 +3x+ 2x +1
=>-11x + 3 = 5x +1
=> - 16x = - 2
=> x= 1/8
I hope this answers your question sufficiently. You can show your appreciation by thanking me and following me. Happy learning.
After cross multiplying, we'll get
(2x-3)×(3x-1)= (3x+1)(2x+1)
=> 6x^2 - 2x - 9x+ 3 = 6x^2 +3x+ 2x +1
=>-11x + 3 = 5x +1
=> - 16x = - 2
=> x= 1/8
I hope this answers your question sufficiently. You can show your appreciation by thanking me and following me. Happy learning.
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