solve 2x-3 ,3x-2 ,3(x+4) ,4x+1 ,4(3x+1) ,2x+1
Answers
Answered by
1
Answer:
Given
(2x−1)
(2x−3)
=
(3x+1)
(3x−1)
(2x−3)(3x+1)=(3x−1)(2x−1)
On further calculations , we get ,
6x
2
+2x−9x−3=6x
2
−3x−2x+1
6x
2
−7x−3=6x
2
−5x+1
6x
2
−7x−6x
2
+5x=1+3
−7x+5x=4
−2x=4
We get ,
x=
−2
4
x=−2
Similar questions