Math, asked by Anonymous, 5 months ago

Solve 2x - 3 = x + 2

Give the Explanation...also!!​

Answers

Answered by Anonymous
0

 \huge \mathscr{\orange {\underline {\pink{\underline{Answer :-}}}}}

Given Equation:

2x - 3 = x + 2

Solution:

We have,

\tt\longmapsto{} \sf{2x = x + 2 + 3}

or

\tt\longmapsto{} \sf{2x = x + 5}

or

\tt\longmapsto{} \boxed{\sf{\purple{(Subtracting\: x\: from\: both\: sides↓)}}}

\tt\longmapsto{} \sf{2x - x = x + 5 - x}

or

\tt\longmapsto{} \sf{x = 5}

❤️Explanation:

★ Here we subtracted from both sides of the equation, not a number (constant), but a term involving the variable. We can do this as variables are also numbers. Also, note that subtracting x from both sides amounts to transposing x to L.H.S.

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Answered by SweetCharm
16

 \huge \mathscr{\orange {\underline {\pink{\underline{Answer :-}}}}}

Given Equation:

2x - 3 = x + 2

Solution:

We have,

\tt\longmapsto{} \sf{2x = x + 2 + 3}

or

\tt\longmapsto{} \sf{2x = x + 5}

or

\tt\longmapsto{} \boxed{\sf{\purple{(Subtracting\: x\: from\: both\: sides↓)}}}

\tt\longmapsto{} \sf{2x - x = x + 5 - x}

or

\tt\longmapsto{} \sf{x = 5}

❤️Explanation:

★ Here we subtracted from both sides of the equation, not a number (constant), but a term involving the variable. We can do this as variables are also numbers. Also, note that subtracting x from both sides amounts to transposing x to L.H.S.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

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