Question

solve 2x+3y=0 and 4x-3y=2​

Answer 1

Step-by-step explanation:

Given equations are:

2x+3y=0.....(1)

4x−3y=0.....(2)

Now multiply (1) by (2) we get

4x+6y=0......(3)

Now subtracting (2) from (3), we get

⇒9y=0

⇒y=0

now substitute the y value in (3)

⇒4x+6(0)=0

⇒4x=0

⇒x=0

⇒x+y=0+0

⇒x+y=0