Solve 2x + 3y = 11 and 2x – 4y = -24 and hence find the value of’m’ for which y = mx +3.
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Answers
Given equations are—
- 2x + 3y = 11 ------------(1)
- 2x – 4y = -24 ------------(2)
{ We will solve those equations by Substracting Method }
Now,
eq(1) - eq(2)
→ 2x + 3y - ( 2x - 4y ) = 11-(-24)
→ 2x + 3y - 2x + 4y = 11+24
→ 7y = 35
→
† Putting the value of y in eq(1) , we get
→ 2x + 3 × 5 = 11
→ 2x + 15 = 11
→ 2x = 11 - 15
→ 2x = - 4
→
Hence ,
★ x = -2
★ y = 5
Again ,
• y = mx + 3
Substituting the values ,
☞ 5 = m× (-2) + 3
→ -2m = 2
→
Answer:
Given equations are—
2x + 3y = 11 ------------(1)
2x – 4y = -24 ------------(2)
{ We will solve those equations by Substracting Method }
Now,
eq(1) - eq(2)
→ 2x + 3y - ( 2x - 4y ) = 11-(-24)
→ 2x + 3y - 2x + 4y = 11+24
→ 7y = 35
→ \bold{\boxed{y\:\:=\:5}}
y=5
† Putting the value of y in eq(1) , we get
→ 2x + 3 × 5 = 11
→ 2x + 15 = 11
→ 2x = 11 - 15
→ 2x = - 4
→ \bold{\boxed{x\:\:=\:-2}}
x=−2
Hence ,
★ x = -2
★ y = 5
Again ,
• y = mx + 3
Substituting the values ,
☞ 5 = m× (-2) + 3
→ -2m = 2
→ \bold{\boxed{m\:\:=\:\:-1}}
m=−1
Step-by-step explanation:
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