Question

solve 2x+3y=11 and 3x+4y=15 by elimination method

Answer 1

(2x+3y=11)x3

-(3x+4y=15)x2

___________

0x+1y=3

___________

Thus y=3

Substitute y=3 in any eq

2x+3x3=11

2x=11-9

x=2/2

Thus x=1 and y=3

Thanks

Sam.

Answer 2

We have,
2x+3y=11 ..........................(i)
3x+4y=15 ..........................(ii)


On multiplying eq.(i) by 3 and eq.(ii) by 2 we get

3(2x+3y)=3×11
=>6x+9y=33 .............(iii)


2(3x+4y)=2×15
=>6x+8y=30 ..............(iv)
Subtracting eq.(iv) ew.(iii) we have

6x+9y-(6x+8y)=33-30
6x+9y-6x-8y=3
y=3


Putting y=3 in eq.(i)

2x+3(3)=11
2x+9=11
2x=11-9
2x=2
x=1



Hence,y=3 and x=1