Question

Solve 2x+3y=11 and 3x-y=5
please solve it in elimination method or cross multiplication method
and send the answer in photo please...
Its very urgent send fast..​

Answer 1

$\mathtt{2x+3y=11 \;\;\;\;\; ----(i)}$

$\mathtt{3x-y=5 \;\;\;\;\; ----(ii)}$

$\texttt{multiplying \; eq \; (ii) \; by} \; \mathtt{3}$

$\mathtt{[3y-y=5]×3}$

$\mathtt{9x-3y=15 \;\;\;\;\; ----(iii)}$

$\texttt{adding \; (i) \& (iii), }$

$\;\;\;\;\;\;\;\;\;\; \mathtt{2x+3y\!\!\!\! \Large{/} \normalsize = 11}$

$\;\;\;\;\;\;\;\; \underline{\;\; \mathtt{9x-3y\!\!\!\!\Large{/} \normalsize = 15}}$

$\;\;\;\;\;\;\;\;\;\; \mathtt{11x = 26}$

$\;\;\; \implies \mathtt{x = \frac{26}{11}}$

$\texttt{Putting} \; \mathtt{x \; = \large\frac{26}{11}} \; \texttt{in \; eq \; (ii),}$

$\mathtt{3×\large \frac{26}{11} \normalsize -y = 5}$

$\implies \mathtt{\large\frac{78}{11} \normalsize -y = 5}$

$\implies \mathtt{y = \large\frac{78}{11} \normalsize -5}$

$\implies \mathtt{y = \large\frac{78-55}{11}}$

$\implies \mathtt{y = \large \frac{23}{11}}$

Answer 2

Step-by-step explanation:

assume that 2x+3y=11 is eqation 1

and

3x-y=5 is equation 2

the coefficients of x and y are not equal so

multiply the coefficient of x in eqation 1 with the eqation 2

and

multiply the coefficient of x in equation 2 with the equation 1

so

6x+9y=33 is equation 1

6x-2y=55

solve these two equations in elemination method

6x+9y=33

6x-2y=55

11y= -22

11y=-22

y=-22/11

=-2/1