Question

Solve 2x+3y=11 and x-2y+12=0 by substitution method and hence find the valve of m for which 2y=mx=10​

Answer 1

Answer:

2x + 3y = 11            (1)

x - 2y = -12             (2)

Multiply  (2) by 2  we get

2x - 4y = -24          (3)

subtract (3) from (1)

7y = 35  

y=5    

Put y= 5 in (1)  

2x+15 =11    

2x = 11-15  

2x = -4    

x = -2

Put the value of x and y in y = mx + 3

we get  5= - 2 m +3

or - 2m -2

or m = -1

Answer 2

Step-by-step explanation:

value of  m =  - 1

Step-by-step explanation:

2x + 3y = 11            (1)

x - 2y = -12             (2)

Multiply  (2) by 2  we get

2x - 4y = -24          (3)

subtract (3) from (1)

7y = 35  

y=5    

Put y= 5 in (1)  

2x+15 =11    

2x = 11-15  

2x = -4    

x = -2

Put the value of x and y in y = mx + 3

we get  5= - 2 m +3

or - 2m -2

or m = -1.

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