Solve 2x + 3y = 11 and x − 2y = −12 algebraically and hence find the value
of ‘m’ for which y = mx + 3
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2x + 3y = 11 ----(1) x-2y = -12 ----(2) (2) ⇒ x = 2y -12 ----(3) Substitute value of x from (3) in (1), we get 2(2y -12) +3y = 11 ⇒ 4y – 24 + 3 y = 11 ⇒7y = 35 ⇒y = 5 Substituting value of y = 5 in equation (3), we get x= 2(5) - 12 = 10 - 12 = -2 Hence x = -2, y=5 is the required solution Now 5= -2m +3 ⇒2m = 3-5 ⇒2m = -2 m = -1Read more on Sarthaks.com - https://www.sarthaks.com/504253/solve-2x-3y-11-and-x-2y-12-algebraically-and-hence-find-the-value-of-m-for-which-y-mx-3
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