Solve 2x+3y=11and 2x-4y=-24and hence find the value of 'm' for which y=mx+3.
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Answer:
2x+3y=11 _ _ _ _ equation 1
2x-4y=-24 _ _ _ equation 2
On subtracting equation 2 from equation 1,we get:-
7y=35
y=5
From equation 1,
2x+3y=11
2x+3*5=11
2x+15=11
2x=11-15
2x=-4
x=-4/2
x=-2
ATQ
y=mx+3
5=-2m+3
5-3=-2m
2=-2m
m=2/-2
m=-1
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