Solve : 2x – 3y = 19 and 3x – 2y – 21 = 0 by substitution method.
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2x – 3y = 19........(1)
3x – 2y – 21 = 0
3x – 2y =21 .....(2)
by eq(2)
3x=21+2y
x= 21+2y/3........(3)
put the value from (3) to in (1)
2(21+2y/3)-3y=19
42+4y-9y=57
-5y=15
y=-3
put value of y in (3)
x=21+2(-3)/3
x=21-6/3
x=5
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