Solve
2x + 3y - 2 = 4
4x+6y+z=11
X-3y+z=-1
Answers
Answer:
(A) x +2z = 4 This is equation (A), our first equation
− 2x − 2y +3z = 5 Using the second two equations
5x +2y − z = 3 Add the second two equations
(B) 3x +2z = 8 This is equation (B), our second equation
(A) x +2z = 4 Using (A) and (B) we will solve this system.
(B) 3x +2z = 8 We will solve by addition
− 1(x +2z) =(4)( − 1) Multiply (A) by − 1
− x − 2z = − 4
− x − 2z = − 4 Add to the second equation, unchanged
3x +2z = 8
2x = 4 Solve, divide by 2
2 2
x = 2 We now have x! Plug this into either(A) or(B)
(2) +2z = 4 We plug it into (A),solve this equation,subtract 2
− 2 − 2
2z = 2 Divide by 2
2 2
z = 1 We now have z! Plug this and x into any original equation
3(2) +2y − (1)= − 1 We use the first, multiply 3(2) =6 and combine with − 1
2y + 5= − 1 Solve,subtract 5
− 5 − 5
2y = − 6 Divide by 2
2 2
y = − 3 We now have y!
(2, − 3, 1) Our Solution
As we are solving for x, y, and z we will have an ordered triplet (x, y, z) instead of
Answer:
(A) x +2z = 4 This is equation (A), our first equation
− 2x − 2y +3z = 5 Using the second two equations
5x +2y − z = 3 Add the second two equations
(B) 3x +2z = 8 This is equation (B), our second equation
(A) x +2z = 4 Using (A) and (B) we will solve this system.
(B) 3x +2z = 8 We will solve by addition
− 1(x +2z) =(4)( − 1) Multiply (A) by − 1
− x − 2z = − 4
− x − 2z = − 4 Add to the second equation, unchanged
3x +2z = 8
2x = 4 Solve, divide by 2
2 2
x = 2 We now have x! Plug this into either(A) or(B)
(2) +2z = 4 We plug it into (A),solve this equation,subtract 2
− 2 − 2
2z = 2 Divide by 2
2 2
z = 1 We now have z! Plug this and x into any original equation
3(2) +2y − (1)= − 1 We use the first, multiply 3(2) =6 and combine with − 1
2y + 5= − 1 Solve,subtract 5
− 5 − 5
2y = − 6 Divide by 2
2 2
y = − 3 We now have y!
(2, − 3, 1) Our Solution
As we are solving for x, y, and z we will have an ordered triplet (x, y, z) instead of
Step-by-step explanation: