Math, asked by fathimapulikkal27, 10 months ago

solve 2x-3y=3 4x-y=11 by matrix method​

Answers

Answered by gurpreetkaur79359
8

Answer:

Step-by-step explanation:

Attachments:
Answered by anurag432
2

Answer:

2x-3y=3

4x-y=11

Here x=3, y=1.

Step-by-step explanation:

Given 2x-3y=3 4x-y=11

let AX = B

where A = \left[\begin{array}{ccc}2&-3\\4&-1\\\end{array}\right]  B =  \left[\begin{array}{ccc}3\\11\\\end{array}\right]

║A║ = (-2+12) = 10

║A1║= \left[\begin{array}{ccc}3&-3\\11&-1\\\end{array}\right]    ║A2║= \left[\begin{array}{ccc}2&3\\4&11\\\end{array}\right]

║A1║=(-3+33) = 30

║A2║= (22-12) = 10

Using Cramer's rule

X = ║A1║÷║A║= 30÷10 = 3

Y = ║A2║÷║A║ = 10÷10 = 1

therefore x = 3, y = 1.

Cramer's rule is an important method applied to solve a system of equations. In this method, the values of the variables in the system are to be calculated using the determinants of matrices. Thus, Cramer's rule is also known as the determinant method.

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