Question

solve (2x+3y-4z) square​

Answer 1

Step-by-step explanation:

explation is in picture

Answer 2

Given :  (2x + 3y - 4z)²

• Identity : (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

                Here, a = 2x, b = 3y, c = - 4z

⇒ (2x)² + (3y)² + (- 4z)² + 2(2x)(3y) + 2(3y)(- 4z) + 2(- 4z)(2x)

⇒ 4x² + 9y² + 16z² + 12xy - 24yz - 16zx