Question

solve 2x+3y+5=0 and 3x-2y-12=0 by suitble method

Answer 1

2x+3y=-5.......(i)

3x-2y=12........(ii)

From (i)

2x=-5-3y

$x = \frac{ - 5 - 3y}{ 2}$

put in (ii)

$3 (\frac{ - 5 - 3y}{2} ) - 2y = 12$

$- 15 - 9y - 4y = 24$

-15-13y=24

-15-24=13y

13y=-39

y=-3

$x = \frac{ - 5 - 3 \times ( - 3)}{2} \\ x = \frac{ - 5 + 9}{2} \\ x = \frac{4}{2} \\ x = 2$

Hope it helps you ☺✌✌

Answer 2

Answer:

Step-by-step explanation:elimination

2x+3y=-5........(1)

3x-2y=12...(2)

Add eq 1 and 2 we get

5x+1y=7.........(3)

Now

Subtract 1 from 2,we get

X-5y =17......(4)

Multiply 3 by 5 we get,

25x+5y=35....(5)

Now ,

Add 4 and 5 we get,

26x=52

X=2

now ,

Substitute x=2 in eq3

5x+1y=7

5×2+1y=7

10+y=7

y=7-10

y=-3

(x,y)=(2,-3)