Question

Solve: (2x + 3y-5)² + (3x + 2y – 5)² = 0​

Answer 1

Answer:

RHS=LHS

Step-by-step explanation:

Step-by-step explanation:LHS,

(2x+3y-5)²+(3x+2y-5)²=0

=> (4x+9y-25)+(9x+4y-25)=0

9y-25)+(9x+4y-25)=0=>(4x+9x)+(9y+4y)-(25-25)=0 [taking common]

9y-25)+(9x+4y-25)=0=>(4x+9x)+(9y+4y)-(25-25)=0 [taking common]=>13x+13y-0=0

9y-25)+(9x+4y-25)=0=>(4x+9x)+(9y+4y)-(25-25)=0 [taking common]=>13x+13y-0=0=>13x+13y=0

9y-25)+(9x+4y-25)=0=>(4x+9x)+(9y+4y)-(25-25)=0 [taking common]=>13x+13y-0=0=>13x+13y=0=>x+y=13-13

=> x+y=0

Therefore LHS=RHS

Answer 2

Answer:

(2x + 3y-5)² + (3x + 2y – 5)² = 0