Solve: 2x + 3y = 5 and 5x + 2y = 7 by elimination method
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THANKS FOR THE QUESTION :
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=> 2X + 3Y = 5 ....................1
=> 5X + 2Y = 7 ....................2
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=> MULTIPLY EQUATION 1 BY 5
=> WE GET ,
=> 10X + 15Y = 25
=> 2 ( 5X ) + 15Y = 25 ..................3
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=> NOW, TAKE EQN 2 AND MAKE IT FOR THE SUBSTITUTION :
=> 5X + 2Y = 7
=> 5X = 7 - 2Y ........................4
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PUT THE VALUE OF 5X IN EQN NO. 3
=> 2 ( 7 - 2Y ) + 15Y = 25
=> 14 - 4Y + 15Y = 25
=> 14 + 11Y = 25
=> 11Y = 25 - 14
=> 11Y = 11
=> Y = 11 / 11
=> Y = 1
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PUT Y = 1 IN EQN 1
=> 2X + 3*1 = 5
=> 2X + 3 = 5
=> 2X = 5-3
=> 2X = 2
=> X = 2/2
=> X = 1
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HOPE IT WILL HELP U.....
THANKS AGAIN ......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
=> 2X + 3Y = 5 ....................1
=> 5X + 2Y = 7 ....................2
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
=> MULTIPLY EQUATION 1 BY 5
=> WE GET ,
=> 10X + 15Y = 25
=> 2 ( 5X ) + 15Y = 25 ..................3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
=> NOW, TAKE EQN 2 AND MAKE IT FOR THE SUBSTITUTION :
=> 5X + 2Y = 7
=> 5X = 7 - 2Y ........................4
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PUT THE VALUE OF 5X IN EQN NO. 3
=> 2 ( 7 - 2Y ) + 15Y = 25
=> 14 - 4Y + 15Y = 25
=> 14 + 11Y = 25
=> 11Y = 25 - 14
=> 11Y = 11
=> Y = 11 / 11
=> Y = 1
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT Y = 1 IN EQN 1
=> 2X + 3*1 = 5
=> 2X + 3 = 5
=> 2X = 5-3
=> 2X = 2
=> X = 2/2
=> X = 1
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
HOPE IT WILL HELP U.....
THANKS AGAIN ......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
Anonymous:
plz solve my other questions
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