Question

solve 2X-3y=7 and x+y=1 by elimination method​

Answer 1

Answer:

x= 2 y= 1

Step-by-step explanation:

2x - 3y = 7. x1

=> 2x- 3y = 7

x + y = 1. x3

3x+ 3y = 3

2x - 3 y. = 7

3x + 3y. = 3

__________

5x + 0 = 10

x= 2

substitute the value of x in any of the given eqn

we get,

y = 1

ig this is crt

hope this helps u mate!

if s, pls mark me as a brainiest :)

Answer 2

Given,

2x-3y=7 i

x+y=1 ii

step 1

multiply eqn ii by 2 to make same coefficient

2x-3y=7

2(x+y)=1

2x-3y-=7

2x+2y=1

step 2 changing sign

2x-3y=7

-2x-2y=-1

-5y=6

y=6÷-5

putting the value of y in eqn i we get

2x-3y=7

2x-3(-6÷5)=7

2x+18÷5=7

(10x+18)5=7

10x+18=35

10x=35-18

x=17÷10

thus y=6÷5and x=17÷10