Math, asked by veer81, 1 year ago

solve 2x-3y=7 and x+y=1 by the method of substitution

Answers

Answered by vanshikabu
10
2x=7-3y
X=7-3y/2
Substituting the value of x in x+y=1
7-3y/2+y=1
7-3y+2y=2
7-(-1y)=2
1y=2-7
Y=-5
Putting the value of y in 2x-3y=7
2x-(-5)=7
2x+5=7
2x=7-5
X=1

vanshikabu: sry
Anonymous: ok no prblm.....but your answer is wrong.....let me check
vanshikabu: ok
Anonymous: x = 7 + 3y / 2
Anonymous: 2nd line mai
vanshikabu: ok
Anonymous: hmm...
vanshikabu: I checked
vanshikabu: it is wrong
Anonymous: okk
Answered by Anonymous
9
Hey friend...!! here's your answer
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2x - 3y = 7 ----------1
x + y = 1 -----------2


By Substitution Method ,

from equation 2

x = 1 - y ------------3

Put the value of equation 3 in equation 1

2(1 - y ) - 3y = 7

2 - 2y - 3y = 7

-5y = 5

y = -1

Put the value of y in equation 3

x = 1 - (- 1)
x = 2

So that the value of x is 2 and value of y is - 1
____________________
#hope its help you dear#




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