solve 2x-3y=7 and x+y=1 by the method of substitution
Answers
Answered by
10
2x=7-3y
X=7-3y/2
Substituting the value of x in x+y=1
7-3y/2+y=1
7-3y+2y=2
7-(-1y)=2
1y=2-7
Y=-5
Putting the value of y in 2x-3y=7
2x-(-5)=7
2x+5=7
2x=7-5
X=1
X=7-3y/2
Substituting the value of x in x+y=1
7-3y/2+y=1
7-3y+2y=2
7-(-1y)=2
1y=2-7
Y=-5
Putting the value of y in 2x-3y=7
2x-(-5)=7
2x+5=7
2x=7-5
X=1
vanshikabu:
sry
Answered by
9
Hey friend...!! here's your answer
_________________________
2x - 3y = 7 ----------1
x + y = 1 -----------2
By Substitution Method ,
from equation 2
x = 1 - y ------------3
Put the value of equation 3 in equation 1
2(1 - y ) - 3y = 7
2 - 2y - 3y = 7
-5y = 5
y = -1
Put the value of y in equation 3
x = 1 - (- 1)
x = 2
So that the value of x is 2 and value of y is - 1
____________________
#hope its help you dear#
_________________________
2x - 3y = 7 ----------1
x + y = 1 -----------2
By Substitution Method ,
from equation 2
x = 1 - y ------------3
Put the value of equation 3 in equation 1
2(1 - y ) - 3y = 7
2 - 2y - 3y = 7
-5y = 5
y = -1
Put the value of y in equation 3
x = 1 - (- 1)
x = 2
So that the value of x is 2 and value of y is - 1
____________________
#hope its help you dear#
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