solve 2x+3y=7and3x-y=5 using substitution method
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Hi mate.. here is ur answer
Step-by-step explanation:
Let 2x+3y=7 be eq 1 And 3x-y=5 be eq 2
From eq1 --> 2x=7-3y
---->x=7-3y/2 ---------> 3
Substituting 3 in 2
we get... ,. 3(7-3y/3)-y-5=0
21-9y-3y-15=0 ( bye taking lcm =3 and taking to rhs)
6-12y=0. --> -12y= -6,
Therefore y=2. ----> 4
substituting 4 in 3
x=7-3×4/3=7-13/3.
x=6/2
therefore x=3
Therefore x=3 and y=2. pls mark brainlist
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