Math, asked by roop21, 10 months ago

solve 2x-3y=8 and 6x-6y=9 by elimination method ​

Answers

Answered by saurabhsemalti
2

Step-by-step explanation:

2x - 3y = 8.........(1) \\ 6x - 6y = 9.....(2) \\ multiply \: (1)by \: 3 \\ (1) \: becomes \\ 6x - 9y = 24....(3) \\ now \: we \: have \\ 6x - 9y = 24.......(3) \\ 6x - 6y = 9.......(2) \\ subtracting \: (2) \: from \: (3) \:  \\ 6x - 9y - (6x - 6y) = 24 - 9 \\  - 15y = 15 \\ y =  - 1 \\ putting \: in \: (2) \\ 6x - 6y = 9 \\ 6x - 6( - 1) = 9 \\ 6x + 6 = 9 \\ 6x = 3 \\ x =  \frac{3}{6}  \\x =   \frac{1}{2}

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Answered by sethipratap980
0

1)Enter the equations.2)Multiply each equation by a number to get the lowest common multiple for the coefficients of one variable.3)Subtract Equation 4 from Equation 3.4)Substitute Equation 5 in Equation 1.

ans:-(½,-1)

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