Solve 2x + 3y = 8 and x-4y=7 by substitution
method.
Answers
Answered by
3
hey
2x+3y=8-------1)
x-4y=7---------2)
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x-y=15
x=15+y
put in 2 equ.
15+y-4y=7
-3y=7-15
-3y= -8
y = 8/3
.x=15+8/3
x=45+8
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3
x= 53/3
Answered by
2
Answer:
x-4y=7
x=7+4y substitute in eqn 1
2x+3y=8
2(7+4y)=8
14+8y=8
14-8=-8y
-6=-8y
y=14
substitute y=14 in x-4y=7
x-4y=7
x-4(14)=7
x-56=7
x=7+56
x=63
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