Question

solve (2x-3y-z)^2-(z-x)^2​

Answer 1

$\huge\bold{ANSWER~:}$

$= {(2x - 3y - z)}^{2} - {(z - x)}^{2} \\ \\ =( {(2x)}^{2} + {( - 3y)}^{2} + {( - z)}^{2} + 2(2x)( - 3y) + 2( - 3y)( - z) + 2( - z)(2x) ) - ( {z}^{2} - 2xz + {x}^{2} ) \\ \\ = 4 {x}^{2} - 9 {y}^{2} - {z}^{2} - 12xy - 6yz - 4xz - {z}^{2} + 2xz - {x}^{2} \\ \\ = 3 {x}^{2} - 9 {y}^{2} - {2z}^{2} - 12xy - 6yz + 2xz$

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