Math, asked by Thakshaya7734, 9 months ago

Solve (2x-4)/4=(3y-2)/2, 4x-3/2=(6-y)/3=17/6

Answers

Answered by priya027
1

Answer:

x=63/74 and y=21/74 this is the value of x and y by the method of elimination

Answered by satya11103
2

(2x -4)/4 = (3y-2)/2

2x-4 = (3y-2)4/2

2 cancelled 4, 2 times so, we have

2x-4 = (3y-2)2

2x-4 = 6y-4

2x = 6y-4+4

2x = 6y

x=6y/2

since, x= 3y

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