Solve (2x-4)/4=(3y-2)/2, 4x-3/2=(6-y)/3=17/6
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1
Answer:
x=63/74 and y=21/74 this is the value of x and y by the method of elimination
Answered by
2
(2x -4)/4 = (3y-2)/2
2x-4 = (3y-2)4/2
2 cancelled 4, 2 times so, we have
2x-4 = (3y-2)2
2x-4 = 6y-4
2x = 6y-4+4
2x = 6y
x=6y/2
since, x= 3y
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