Solve 2x+4y-10=0;3x+6y-12=0
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Answer:
9
Step-by-step explanation:
let 2x+4y+10=0 be (I)
and 3x+6y-12=0 be (ii)
Then, subtract ii and I,
EQ.i. 2(x+2y+5)=0
EQ.ii. 3(x+2y-4)=0
Send 2 to zero then we will have eq.i. x+2y+5=0
EQ.ii. x+2y-4=0
so subtract eq.i. and eq.ii
Then we will have 9...
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