solve 2x+4y=3,4x+8y=6
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2x + 4y = 3 and 4x + 8y = 6
a₁ = 2 ; b₁ = 4 ; c₁ = -3
a₂ = 4 ; b₂ = 8 ; c₂ = -6
a₁/a₂ = 2/4 = ½
b₁/b₂ = 4/8 = ½
c₁/c₂ = -3/-6 = ½
a₁/a₂ = b₁/b₂ = c₁/c₂
It has infinitely many solutions.
a₁ = 2 ; b₁ = 4 ; c₁ = -3
a₂ = 4 ; b₂ = 8 ; c₂ = -6
a₁/a₂ = 2/4 = ½
b₁/b₂ = 4/8 = ½
c₁/c₂ = -3/-6 = ½
a₁/a₂ = b₁/b₂ = c₁/c₂
It has infinitely many solutions.
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2x + 4y = 3. ______(1)
4x + 8y = 6. ______(2)
Multiplying eqn (1) by 2
We get,
4x + 8y = 6 ______(3)
The equation (2) and equation (3) are same.
Thus, it will have infinite solutions.
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