solve (2x+4y-6)=(2x-5y+3)dx
Answers
Answer:
Explanation:Simplifying
(2x + -5y + 3) * dx + -1(2x + 4y + -6) * dy = 0
Reorder the terms:
(3 + 2x + -5y) * dx + -1(2x + 4y + -6) * dy = 0
Reorder the terms for easier multiplication:
dx(3 + 2x + -5y) + -1(2x + 4y + -6) * dy = 0
(3 * dx + 2x * dx + -5y * dx) + -1(2x + 4y + -6) * dy = 0
Reorder the terms:
(3dx + -5dxy + 2dx2) + -1(2x + 4y + -6) * dy = 0
(3dx + -5dxy + 2dx2) + -1(2x + 4y + -6) * dy = 0
Reorder the terms:
3dx + -5dxy + 2dx2 + -1(-6 + 2x + 4y) * dy = 0
Reorder the terms for easier multiplication:
3dx + -5dxy + 2dx2 + -1dy(-6 + 2x + 4y) = 0
3dx + -5dxy + 2dx2 + (-6 * -1dy + 2x * -1dy + 4y * -1dy) = 0
Reorder the terms:
3dx + -5dxy + 2dx2 + (-2dxy + 6dy + -4dy2) = 0
3dx + -5dxy + 2dx2 + (-2dxy + 6dy + -4dy2) = 0
Reorder the terms:
3dx + -5dxy + -2dxy + 2dx2 + 6dy + -4dy2 = 0
Combine like terms: -5dxy + -2dxy = -7dxy
3dx + -7dxy + 2dx2 + 6dy + -4dy2 = 0
Solving
3dx + -7dxy + 2dx2 + 6dy + -4dy2 = 0
Solving for variable 'd'.
Move all terms containing d to the left, all other terms to the right.
Factor out the Greatest Common Factor (GCF), 'd'.
d(3x + -7xy + 2x2 + 6y + -4y2) = 0