Math, asked by bhavyavikram22, 7 months ago

Solve: 2x + 5y = 15 ; 6x – 3y = 5 using elimination method.

Answers

Answered by arhan12345
0

Step-by-step explanation:

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Answered by IIMidnightHunterII
4

Answer:

2x + 5y = 15.....i \\ 6x - 3y = 5.......ii \\  \\ multiply \: eq \: i \: by \: 3 \\  3(2x + 5y) = 15 \times 3 \\ 6x + 15y = 45....iii \\  \\ multiply \: eq \:  ii \: by \: 5 \\ 5(6x - 3y) = 5 \times 5 \\ 30x - 15y = 25.....iv \\  \\ adding \: eq \: iii \: and \: iv \\  \\ \:  6x  + 15y = 45 \\ ( + ) \: 30x - 15y = 25 \\  \\</p><p> 36x = 70 \\ </p><p>x =  \frac{70}{36}  =  \frac{35}{18}  \\  \\ putting \: value \: of \: x \: in \: eq \: i \\  \\ 2 \times  \frac{35}{18}  + 5y = 15 \\  \\  \frac{35}{9}  + 5y = 15 \\  \\ 5y = 15 -  \frac{35}{9} \\  \\ 5y =   \frac{15 \times 9  - 35}{9}  \\  \\ 5y =  \frac{135 - 35}{9}  \\  \\ 5y =  \frac{100}{9}  \\  \\ y =  \frac{100}{9 \times 5}  \\  \\ y =  \frac{20}{9}

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