Question

solve 2x=5y+4 and 3x-2y+16 by substitution method

Answer 1

Hope this will help you.

Answer 2

Answer:

2x=5y+4.

3x-2y+16

Here we can write that

2x-5y-4=0....(1)

3x-2y+16 ......(2)

now taking equation 1

we get

2x-5y-4=0

2x-5y=4

2x=5y+4

x=5y+4/2.....(3)

Now substituting the value of x in equation 1

we get

3(4+5y)/2-2y+16=0

12+15y-4y+32=0

15y-4y+12+32=0

11y+44=0

11y=-44

y=-44/11= -4

so the value of y is -4

now putting the value of y in equation 1

we get

2x-5*(-4)-4=0

2x+20-4=0

2x=-16

X=-16/2=-8

So the value of x = -8

y= -4