Question

solve:(2x-6) (3x+1)=(3x-2)(2x-1)​

Answer 1

Answer:

Mark as brainliest answer.

Step-by-step explanation:

→ (2x - 6)(3x + 1) = (3x - 2)(2x - 1)

→ (2x × 3x + 2x × 1 - 6 × 3x - 6 × 1) = (3x × 2x - 3x × 1 - 2 × 2x + 2 × 1)

→ (6x² + 2x - 18x - 6) = (6x² - 3x - 4x + 2)

→ (6x² - 16x - 6) = (6x² - 7x + 2)

→ 6x² - 6x² - 16x + 7x - 6 - 2

→ -16x + 7x - 6 - 2

→ -9x - 8

→ -9x = 8

→ x = 8/-9

→ x = -8/9

Answer 2

Step-by-step explanation:

Multiplying each term in one bracket with each term in another bracket:

For eg: In (2x-6)(3x+1)

I will take 2x and multiply it with both 3x and 1 in the second bracket.

Then I will take -6 and again multiply it with 3x and 1 in the second bracket.

6x^ + 2x -18x -6 = 6x^ - 3x -4x +2

(6x^ gets cancelled)

-16x -6 = -7x +2

-2 -6 = 16x -7x

-8 = 9x

x = -8/9

Note: ^ denotes square