Math, asked by prajapatipravesh, 4 months ago

solve - 2x + 6y = 16 and -4x-3y =2 by simultaneous equation​

Answers

Answered by kumawatpriyanka66
2

Step-by-step explanation:

-2x + 6 y = 16 .........1

-4x - 3y= 2. ............2

Now substitute the value of X from eq 1

x=16-6y/-2

put the value of X in eq 2

-4(16-6y/-2) = 2

16-6y / -2 =2/-4

16-6y= 1/-2 ×-2

-6y =-16

y=-16/-6

y=8/3

Now you put the value of y in any of the given eq and you will get the value of x ..........

Answered by deepakdeshmukh1045
0

answer :

(-2,2)

step by step explanation :

-4x-3y=2 (multiply by 2)

=-8x-6y =4

-8x-6y =4

+-2x+6y=16

-10x+0y = 20

x= -20/10

x= -2

put x=-2 in eq. (i)

-2(-2)+6y = 16

4+6y = 16

6y = 16-4

6y = 12

y= 12/6

y= 2

then,

(x, y) = (-2,2)

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