Solve : √(2x+9) = 13 - x
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√2x+9 + x = 13
√2x+9 = 13-x
squaring both sides
2x + 9 = (13-x)²
2x+9 = 169 - 26x + x²
2x +26x +9 - 169 = x²
28x-160 = x²
by using factorization method
x²-28x+160 = 0
x² - 20x - 8x +160 = 0
x(x-20) -8(x-20) = 0
(x-20)(x-8) = 0
x = 20 and x= 8
hope it help
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Answered by
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√(2x+9)=13-x
squaring both sides,
we get
2x+9=(13-x)^2
2x+9=169+x^2-26x
x^2-28x+160=0
you can solve this by mid term splitting
x^2-20x-8x+160=0
x(x-20)-8(x-20)=0
(x-8)(x-20)=0
x=8 or 20
squaring both sides,
we get
2x+9=(13-x)^2
2x+9=169+x^2-26x
x^2-28x+160=0
you can solve this by mid term splitting
x^2-20x-8x+160=0
x(x-20)-8(x-20)=0
(x-8)(x-20)=0
x=8 or 20
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