Question

solve - 2x[x^2 by 3]^-3 by2 ​

Answer 1

Answer:

6$\sqrt{3}$

Step-by-step explanation:

2x$[(x^2)/3]^{-3/2}$

2x$[(x^2)/3]^{-3*1/2}$

2x$\sqrt{[(x^2)/3]^{-3} }$

2x$\sqrt{(3^3)/{(x^2)^3}$

2x$\sqrt{[(3^3)/{(x^2)*(1^3)}]}$

[(2x)(3)/(x)]$\sqrt{3}$

6$\sqrt{3}$  => Answer

Hope it helps.