Question

solve 2x+y=14 and 3y=33+x by subsitution method​

Answer 1

Answer:

2x+y=14

x+y=14/2

x+y=7

x=7-y,

y=7-x

3y=33+x

3y-x=33

y-x=33/3

y-x=11

y=11+x,

x=y-11

Answer 2

Answer:

9/7

Step-by-step explanation:

Given ,

2x+y =14 -(1)

and 3y=33+x -(2)

From equation no. (2) , we get that ,

3y= 33+ x

y =(33+x)÷3 -(3)

Put value of y in equation no. (1)

2x+y=14

2x +(33+x)÷3 =14

6x+33+x =42

7x+33 = 42

7x=42-33

7x =9

x=9/7

Put value of x in equation no. (3) , we get that ,

y =(33+9/7) ÷3

y ={(231/7)+(9/7)}÷3

y =240/7×3

y = 80/7