Question

solve : 2x+y=2 , 3x-y=7 ​

Answer 1

Answer:

2x+y=−2

2x=−2−y

x=

2

−2−y

=>equation1

\begin{gathered}3x - y = 7 \\ 3x = 7 + y \\ x = \frac{7 + y}{3} = > equation \: 2\end{gathered}

3x−y=7

3x=7+y

x=

3

7+y

=>equation2

Now, equation 1 = equation 2

\begin{gathered}\frac{ - 2 - y}{2} = \frac{7 + y}{3} \\ 3( - 2 - y) = 2(7 + y) \\ - 6 - 3y = 14 + 2y \\ - 3y - 2y = 14 + 6 \\ - 5y = 20 \\ y = \frac{20}{ - 5} = - 4\end{gathered}

2

−2−y

=

3

7+y

3(−2−y)=2(7+y)

−6−3y=14+2y

−3y−2y=14+6

−5y=20

y=

−5

20

=−4

\begin{gathered}x = \frac{7 + y}{3} \\ x = \frac{7 - 4}{3} \\ x = \frac{3}{3} = 1\end{gathered}

x=

3

7+y

x=

3

7−4

x=

3

3

=1