Question

solve 2x-y=2 and x+3y=15 ​

Answer 1

Explanation...

• 2x-y=2…Equation 1

• x+3y=15…Equation 2

~ Firstly putting 0 as x in Equation 1

➟ 2x-y = 2

➟ 2(0)-y = 2

➟ 0-y = 2

➟ -y = 2-0

➟ -y = 2

➟ y = -2

• We get coordinates as (0,-2)

~ Now putting 0 as y in Equation 1

➟ 2x-y = 2

➟ 2x-0 = 2

➟ 2x = 2

➟ x = 2/2

➟ x = 1

• We get coordinates as (1,0)

~ Now putting 0 as x in Equation 2

➟ x+3y = 15

➟ 0+3y = 15

➟ 3y = 15

➟ y = 15/3

➟ y = 5

• We get (0,5) as coordinate

~ Now putting 0 as y in Equation 2

➟ x+3y = 15

➟ x+3(0) = 15

➟ x+0 = 15

➟ x = 15

• We get coordinates as (15,0)

They intersect at (3,4)

Answer 2

Answer:

Answer is below

Step-by-step explanation:

2x-y=2 ... equation (1)

x+3y=15 ... equation (2)

multiply equation (2) by 2

therefore, we get

2x+6y=30 ... equation (3)

add equation (1) from (3)

2x+6y=30

— 2x-y=2

____________

7y=28

therefore, y=4

consider equation (1)

2x-y=2

2x-4=2

2x=2+4=6

therefore, x=3

therefore, solution is (X, Y)=(3,4)

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