Solve 2x-y=3 and x+3y=5
Answers
Answered by
0
Answer:
2
x
+
y
=
3
2
x
−
2
x
+
y
=
3
−
2
x
0
+
y
=
3
−
2
x
y
=
3
−
2
x
Step 2) Substitute
(
3
−
2
x
)
for
y
in the second equation and solve for
x
:
x
−
3
y
=
5
becomes:
x
−
3
(
3
−
2
x
)
=
5
x
−
(
3
⋅
3
)
+
(
3
⋅
2
x
)
=
5
x
−
9
+
6
x
=
5
1
x
+
6
x
−
9
=
5
(
1
+
6
)
x
−
9
=
5
7
x
−
9
=
5
7
x
−
9
+
9
=
5
+
9
7
x
−
0
=
14
7
x
=
14
7
x
7
=
14
7
7
x
7
=
2
x
=
2
Step 3) Substitute
2
for
x
in the solution to the first equation at the end of Step 1 and calculate
y
:
y
=
3
−
2
x
becomes:
y
=
3
−
(
2
⋅
2
)
y
=
3
−
4
y
=
−
1
The Solution Is:
x
=
2
and
y
=
−
1
Or
(
2
,
−
1
)
Answered by
2
Answer:
1st equation
2x-y=3
=> y=2x-3
2nd equation,
x+3y=5
putting the value of y in 2nd equation
x+3(2x-3)=5
=> x+6x-9=5
=> 7x=5+9
=> 7x=14
=> x=14/7
=> x=2
y=2x-3=2.2-3=4-3=1
so, x=2 , y = 1
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