Solve: 2x-y=(-3) and y=2x-3/2 by substitution method.
DevarshiJoshi:
Answer to this question is needed urgently
Answers
Answered by
5
Hey Mate ✌
Here's your answer friend,
2x - y = (-3) ......(1)
and y = 2x - 3/2
==> 2y = 4x - 3 ......(2)
==> From (1) we get,
2x + 3 = y..... (3)
==> Therefore,
by substituting (3) in eq(2) we get,
==> 2y = 4x - 3
==> 2[2x + 3] = 4x - 3
==> 4x + 6 = 4x - 3
==> 4x - 4x = -3 -6
==> 0 = -9
therefore, there are no specific values of X and y.
⭐ Hope it helps you : ) ⭐
Here's your answer friend,
2x - y = (-3) ......(1)
and y = 2x - 3/2
==> 2y = 4x - 3 ......(2)
==> From (1) we get,
2x + 3 = y..... (3)
==> Therefore,
by substituting (3) in eq(2) we get,
==> 2y = 4x - 3
==> 2[2x + 3] = 4x - 3
==> 4x + 6 = 4x - 3
==> 4x - 4x = -3 -6
==> 0 = -9
therefore, there are no specific values of X and y.
⭐ Hope it helps you : ) ⭐
Answered by
3
2x - y = - 3
2x - (2x-3/2) = - 3
2x - 2x+3/2 = - 3
4x - 2x+3/2 = - 3
2x+3/2 = - 3
2x+3 = - 6
2x = - 9
x =-9/2
2×-9/2 - y= - 3
-18/2 - y =-3
-18 - 2y /2= - 3
-18 - 2y =-6
-2y = 12
y = 12/-2
y = - 6
2x - (2x-3/2) = - 3
2x - 2x+3/2 = - 3
4x - 2x+3/2 = - 3
2x+3/2 = - 3
2x+3 = - 6
2x = - 9
x =-9/2
2×-9/2 - y= - 3
-18/2 - y =-3
-18 - 2y /2= - 3
-18 - 2y =-6
-2y = 12
y = 12/-2
y = - 6
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