solve (2x-y+3z)(4x²+y²+9z²+2xy+3yz-6xz
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Answered by
21
[2x-y+3z][ 4x2+y2+9z2 +2xy+3yz-6xz],
Keeping that x=2x; y=-y; z=3z,
(x+y+z)(x2+y2+z2 -xy -yz -xz)= x3+y3+z3-3xyz
= (2x)3+(-y)3+(3z)3- 3(2x.-y.3z)
= 8x3- y3+ 27z3 + 18xyz Ans.
Keeping that x=2x; y=-y; z=3z,
(x+y+z)(x2+y2+z2 -xy -yz -xz)= x3+y3+z3-3xyz
= (2x)3+(-y)3+(3z)3- 3(2x.-y.3z)
= 8x3- y3+ 27z3 + 18xyz Ans.
Imratlal:
i don't know you say right
we need to rationalise the denominator
how
sorry one is not is answer
boss am editing the previous ques
so solve
have a look there
in which
x=1 √2
now plzz mark my answer as brainlist
Answered by
3
8x3- y3+ 27z3 + 18xyz
is your answer mate
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