Math, asked by Imratlal, 1 year ago

solve (2x-y+3z)(4x²+y²+9z²+2xy+3yz-6xz)

Answers

Answered by ishwarsinghdhaliwal
5
Let a=2x; b=-y; c=3z,
(a+b+c)(a^2+b^2+c^2 -ab -bc -ca)= a^3+b^3+c^3-3abc
= (2x)^3+(-y)^3+(3z)^3- 3(2x)(-y)(3z)
= 8x^3- y^3+ 27z^3+18xyz
SECOND METHOD
☟☟☟☟☟☟☟☟
 = 8x^{3} + 2xy^{2} + 18xz^{2} + 4x^{2} y + 6xyz - 12x^{2}z - 4x^{2}y - y ^{3} - 9yz^{2} - 2xy^{2} - 3y ^{2} z + 6xyz + 12x^{2}z + 3y^{2}z + 27z ^{3 } + 6xyz + 9yz^{2} - 18xz^{2} \\ = 8x ^{3} - y ^{3} + 27z ^{3} + 18xyz
Answered by benjaison2006
0

Answer:

Step-by-step explanation:

please mark as brainest

Attachments:
Similar questions