Solve 2x-y=4,y+2x=8 by substitution method
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Answer:
2x-y=4.........(1)
2x+y=8.........(2)
by taking equation (1)
- x=4+y/2
putting the value of 'x' in equation (2)
- 2x + y = 8
- 2(4+y/2) + y = 8
- 8+ 2y /2 + y = 8
- 8 + 2y + 2y/2 = 8
- 8 + 4y = 16
- 4y = 8
- y = 2
putting the value of 'y' in equation (3)
- x = 4 + 2/2
- x = 4 + 1
- x = 5
Step-by-step explanation:
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2x-y=4-----(1)
2x=4+y
x=(4+y)/2
y+2x=8-----(2)
putting the value of x in (2):
y+2((4+y)/2)=8
y+4+y=8
2y+4=8
2y=4
y=2
x=(4+2)/2
x=6/2=3
so, x=3, and y=2
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