Question

Solve:2x+y =7 ,4x-3y= -1​

Answer 1

Given

• 2x+y=7
• 4x-3y=1

To Find

• Value of x and Y

Solution

let

• $\sf{2x+y=7 \: \: \: \: \: \: - - - - (1)}$
• $\sf{4x-3y=1 \: \: \: \: \: \: - - - - (2)}$

$\\\\\underline{ \sf{ on \: solving \: equation \: 1 \: we \: get}}$

$\\\\\sf{\implies2x+y=7 }$

$\sf{\implies2x=7 - y }$

$\sf{\implies x = \cfrac{ 7 - y}{2} }$

$\\\\ \text{ \bf{ \gray{Putting the value of x in Equation one we get }}}$

$\sf{\implies4x-3y=1}$

$\sf{\implies4 \times \left( \cfrac{7 - y}{2} \right)-3y=1}$

$\sf{\implies2(7 - y )-3y=1}$

$\sf{\implies14 - 2y-3y=1}$

$\sf{\implies - 2y-3y=1 -14 }$

$\sf{\implies - 5y= - 13 }$

$\sf{\implies y= \cfrac{13}{5} }$

$\text{ \bf{ \gray{Putting the value of y in Equation 1 we get }}}$

$\sf{\implies2x + \cfrac{13}{5} = 7}$

$\sf{\implies \cfrac{10x + 13}{5} = 7}$

$\sf{ \implies 10x + 13= 35}$

$\sf{ \implies 10x = 22}$

$\sf{\implies 5x = 11}$

$\sf{ \implies x = \cfrac{11}{5} }$

• $~~~~~~~\underbrace↓_{{\underline{\boxed{\underline{\sf{ \fcolorbox{aqua}{red}{x} = \pink{\cfrac{11}{5}} }}}}}}$

• $~~~~~~~\overbrace↑^{\underline{\boxed{\underline{\sf{\fcolorbox{aqua}{green}{ y}= \orange{\cfrac{13}{5}}}}}}}$

Answer 2

Step-by-step explanation:

x=11/5 and y=13/5

hope this helps you